# int m=(l+h) >> 1; what does it mean?

The expression `int m = (l + h) >> 1;`

is used to calculate the midpoint of two integers `l`

and `h`

, typically in the context of a binary search algorithm or similar logic.

# Breakdown:

`l`

and`h`

are two integer values.`l + h`

calculates the sum of`l`

and`h`

.`>> 1`

is the bitwise right shift operator, which shifts the bits of the result to the right by one position. This effectively divides the sum by 2.

# Meaning:

The expression `(l + h) >> 1`

is equivalent to performing integer division by 2 on the sum of `l`

and `h`

. Therefore, it computes the midpoint between `l`

and `h`

.

# Example:

If `l = 2`

and `h = 10`

, then:

`l + h = 2 + 10 = 12`

`12 >> 1`

shifts the bits of 12 to the right by one position, resulting in`6`

.

So, `m`

would be `6`

, which is the midpoint between `2`

and `10`

.

# Why use `>> 1`

instead of `/ 2`

?

In some systems, bitwise operations like `>> 1`

are slightly faster than division by 2, though in modern compilers, the difference is often negligible. It’s mostly a historical practice from earlier computing where optimization was crucial.